0=8t^2-64t

Solution for 0=8t^2-64t equation:

0=8t^2-64t

We move all terms to the left:

0-(8t^2-64t)=0

We add all the numbers together, and all the variables

-(8t^2-64t)=0

We get rid of parentheses

-8t^2+64t=0

a = -8; b = 64; c = 0;
Δ = b2-4ac
Δ = 642-4·(-8)·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-64}{2*-8}=\frac{-128}{-16}
=+8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+64}{2*-8}=\frac{0}{-16}
=0
$